首页 > > 详细

代做program、代写C/C++语言程序

项目预算:   开发周期:  发布时间:   要求地区:
Lab 4
Pointers
&
Structures
Part I: Nov. 4, 2024
Part II: Nov. 4, 2024
Faculty of Computing, HIT Weihai
Dept. of Computer Science & Technology
4-1/2-0
Pointers as Function Arguments
• Problem: how to exchange two variables using a function (p.95)
• Language points
➢Suppose main (the caller) calls swap (the callee)
➢Argument(s) passed from caller to callee by value
➢NOT vice versa
4-1-1
Faculty of Computing, HIT Weihai, 2024FA
Pointers as Function Arguments
• Problem: how to exchange two variables using a function (p.95)
• Language points
➢Suppose main (the caller) calls swap (the callee)
➢Argument(s) passed from caller to callee by value
➢NOT vice versa
• This program fails because of the wrong idea:
Since the value of a goes to x, afterwards the value of x will
also go back to a automatically; same is true for b and y
a and x are the same variable (not only equal, but they are
just one variable); b and y too
4-1-2
Faculty of Computing, HIT Weihai, 2024FA
Assignment 0: See How It is Wrong
• Use GDB to step through the following program
4-1-3
Faculty of Computing, HIT Weihai, 2024FA
void swap(int x, int y)
{
int temp;
temp = x;
x = y;
y = temp;
}
#include
int main()
{
int x = 3, y = 4;
swap(x, y);
printf("%d %d", x, y);
}
Assignment 0: See How It is Wrong
• Use GDB to step through the following program
➢ Job 1:
✓ When in main, check out the address of x:
(gdb) p &x
✓ When in swap, check out the address of x
✓ Consider: are they the same variable?
➢ Job 2:
✓ Just before leaving swap, check out the value of x:
(gdb) p x
✓ Immediately after getting back to main, check out the value of x
➢ Carefully record the above results and give your observation in the
lab report.
4-1-4
Faculty of Computing, HIT Weihai, 2024FA
Assignment 1: Get the Task Done
• (p.96) By receiving the addresses of arguments from the caller,
the callee manages to reach the original arguments, i.e. a and b
• Step through this program
4-1-5
Faculty of Computing, HIT Weihai, 2024FA
int main()
{
int a = 3, b = 4;
swap(&a, &b);
printf("%d %d", a, b);
}
void swap(int *px, int *py)
{
int temp;
temp = *px;
*px = *py;
*py = temp;
}
Assignment 1: Get the Task Done
(Cont.)
• (p.96) By receiving the addresses of arguments from the caller,
the callee manages to reach the original arguments, i.e. a and b
• Step through this program
➢ When in main, check out the addresses of a and b
➢ When in swap, see if you could still visit a (or b) directly:
(gdb) p a
✓ The reason is because we are now beyond the scope of a and b (§4.4)
✓ Sounds weird, but you just have to remember this rule
➢ However, we are sure to be able to visit a through its address, which is
now held in pointer px:
✓ Try: (gdb) p px and (gdb) p *px
➢ Carefully record the above results and give your observation in the lab
report.
4-1-6
Faculty of Computing, HIT Weihai, 2024FA
Assignment 2: Further Thinking
• Run the following program and try to explain why
• To troubleshoot, step through it using proper GDB commands
• Report your work.
4-1-7
Faculty of Computing, HIT Weihai, 2024FA
int main()
{
int a = 3, b = 4;
swap(&a, &b);
printf("%d %d", a, b);
}
void swap(int *px, int *py)
{
int *temp;
temp = px;
px = py;
py = temp;
}
Arrays of Structures
• Consider the following array of structures:
athlete PRCplayers[] = {
{ "CHANG Yuan", 'F', 0x970624, "boxing", "100" },
{ "JI Bowen", 'M', 0x020222, "canoe", "100" },
{ "LIU Qingyi", 'F', 0x051019, "breaking", "001" },
{ "LIU Yang", 'M', 0x940910, "gymnastics", "110" },
{ "MA Long", 'M', 0x881020, "table tennis", "100" },
{ "PAN Zhanle", 'M', 0x040804, "swimming", "210" },
{ "SHENG Lihao", 'M', 0x041204, "shooting", "200" },
{ "WANG Zongyuan", 'M', 0x011024, "diving", "110" },
{ "WANG Chang", 'M', 0x010507, "badminton", "010" },
{ "ZHANG Yufei", 'F', 0x980419, "swimming", "015" },
};
4-2-1
Faculty of Computing, HIT Weihai, 2024FA
typedef struct {
char *name;
char gender;
unsigned birthday;
char *sport;
char *GSBmedals;
} athlete;
Arrays of Structures
– Comprehensive Problem Solving
• Assignment 3 (choose any ONE task):
➢ Calculate the average number of medals per capita
➢ Find out who has/have won the most gold medals
➢ Find out the youngest male athlete
➢ See if player SUN Yingsha is in this array, using binary search
➢ Rearrange the array into descending order by age, using any algorithm
➢ Show which athletes come from the same sport team, and which sport(s)
➢ Given the subscripts of any two players (0 for CHANG Yuan, …, 9 for
ZHANG Yufei), calculate how many days one is older than the other
➢ Change all surnames from capital letters to lower case except for the
initial letter; and show the full names of all players on the screen
• Report your work.
4-2-2
Faculty of Computing, HIT Weihai, 2024FA
Examples
• Insert the following element into the array:
{ "ZHENG Qinwen", 'F', 0x021008, "tennis", "100" }
➢ Step 1: find the proper position
➢ Step 2: move all elements behind it to make room for the insertion
➢ Step 3: put the new record into this vacated position
➢ Step 4: show the whole array (one more record than before)
4-2-3
Faculty of Computing, HIT Weihai, 2024FA
Examples – insert.c
• Language points
➢When applied to an array, sizeof() evaluates to the total
number of bytes in this array; when applied to a structure,
the result is the # of bytes in this type of structure
➢Structure variables CANNOT be compared directly
✓if (plyr == *pplyr) /* wrong! */
➢Bounds check: should loop condition be > or >=?
✓for (pplyr += n-1; n > 0; n--)
➢printf("%-15s\t%c\t%06x\t%-15s\t%s\n");
✓SHENG Lihao M 041204 badminton_______200
✓WANG Zongyuan M 011024 diving 110
4-2-4
Faculty of Computing, HIT Weihai, 2024FA
_______
__________
_____
___

软件开发、广告设计客服
  • QQ:99515681
  • 邮箱:99515681@qq.com
  • 工作时间:8:00-23:00
  • 微信:codinghelp
热点标签

联系我们 - QQ: 9951568
© 2021 www.rj363.com
软件定制开发网!