首页
网站开发
桌面应用
管理软件
微信开发
App开发
嵌入式软件
工具软件
数据采集与分析
其他
首页
>
> 详细
CSCI1540代写、代做C++设计编程
项目预算:
开发周期:
发布时间:
要求地区:
CSCI1540 Fundamental Computing with C++, Fall 2024/25
Department of Computer Science and Engineering, The Chinese University of Hong Kong
Copyright © 2024 CSE, CUHK Page 1 of 2
Due: 23:59, Thu 17 Oct 2024 File name: kaprekar.cpp Full marks: 100
Introduction
The objective of this assignment is to master the use of selective and nested repetitive control flow.
You will write nested loops to look for Kaprekar numbers.
A Kaprekar number is a positive integer if the digits of the square
2
can be split into two parts
that add up to , where the part formed from the low-order (rightmost) digits of
2
must be nonzero
(although leading zeroes are allowed in the part). For example, 45 is a Kaprekar number,
because 45
2 = 2025 can be split into two parts 20 and 25, with 20 + 25 = 45. As another example,
999 is also a Kaprekar number, because 999
2 = 998001 and 998 + 001 = 999. (Note the loworder
part 001 includes leading zeroes.) However, 31 is not a Kaprekar number, because all three
possible splits of 31
2 = 961 are no good (96 + 1 ≠ 31, 9 + 61 ≠ 31, and 0 + 961 ≠ 31).
Program Specification
The program shall ask for two user inputs and . They are assumed to be always integers. You are
required to use the data type long long instead of int for all integer variables in this assignment,
because a square can easily go overflow with (that is, larger than the upper bound of) the int type.
1. The program first prompts the user to enter an integer . When is not positive, you shall
display a warning message and ask for another input, until is positive. Your program shall look
for Kaprekar number(s) greater than or equal to .
2. Then prompt the user to enter how many Kaprekar numbers the user is looking for. When this
input is not positive, display a warning message and ask for another input, until is positive.
3. After validating inputs and , repeatedly test , + 1, + 2, + 3, … to check whether it is a
Kaprekar number. If so, print out the square and the split of the two parts. (See the upcoming
Sample Runs section for the printing format.) Repeat these checks until Kaprekar numbers are
found and printed. Then program execution ends.
➢ To check whether a number is a Kaprekar number, you progressively check all possible
splits of
2
. E.g., let = 345 and hence
2 = 119025. The first split to check is 11902 and
5; the next split is 1190 and 25; the next split is 119 and 025; and so on.
Note: In this assignment, you are not allowed to: (1) use any functions in the
library, (2)
write any functions other than main(), and (3) use any arrays/vectors (which are not yet taught).
Sample Runs
In the following sample runs, the blue text is user input and the other text is the program printout.
You can try the provided sample program for other input. Your program output should be exactly the
same as the sample program (same text, symbols, letter case, spacings, etc.). Note that there is a
space after the ‘:’ and ‘?’ in the program printout. CSCI1540 Fundamental Computing with C++, Fall 2024/25
Department of Computer Science and Engineering, The Chinese University of Hong Kong
Copyright © 2024 CSE, CUHK Page 2 of 2
Enter an integer: 40↵
How many Kaprekar numbers? 3↵
45^2 = 2025
20 + 25 = 45
55^2 = 3025
30 + 25 = 55
99^2 = 9801
98 + 1 = 99
Enter an integer: -23↵
Input must be +ve! Enter again.
Enter an integer: -1↵
Input must be +ve! Enter again.
Enter an integer: 0↵
Input must be +ve! Enter again.
Enter an integer: 200↵
How many Kaprekar numbers? 0↵
Input must be +ve! Enter again.
How many Kaprekar numbers? 0↵
Input must be +ve! Enter again.
How many Kaprekar numbers? -777↵
Input must be +ve! Enter again.
How many Kaprekar numbers? 5↵
297^2 = 88209
88 + 209 = 297
703^2 = 494209
494 + 209 = 703
999^2 = 998001
998 + 1 = 999
2223^2 = 4941729
494 + 1729 = 2223
2728^2 = 7441984
744 + 1984 = 2728
Submission and Marking
• Your program file name shall be kaprekar.cpp. Submit the file in Blackboard
(https://blackboard.cuhk.edu.hk/).
• Insert your name, student ID, and e-mail as comments at the beginning of your source file.
• You can submit your assignment multiple times. Only the latest submission counts.
• Your program should be free of compilation errors and warnings.
• Your program should include suitable comments as documentation.
• Do NOT share your work to others and do NOT plagiarize. Both senders and plagiarists shall be
penalized.
软件开发、广告设计客服
QQ:99515681
邮箱:99515681@qq.com
工作时间:8:00-23:00
微信:codinghelp
热点项目
更多
代写dts207tc、sql编程语言代做
2024-12-25
cs209a代做、java程序设计代写
2024-12-25
cs305程序代做、代写python程序...
2024-12-25
代写csc1001、代做python设计程...
2024-12-24
代写practice test preparatio...
2024-12-24
代写bre2031 – environmental...
2024-12-24
代写ece5550: applied kalman ...
2024-12-24
代做conmgnt 7049 – measurem...
2024-12-24
代写ece3700j introduction to...
2024-12-24
代做adad9311 designing the e...
2024-12-24
代做comp5618 - applied cyber...
2024-12-24
代做ece5550: applied kalman ...
2024-12-24
代做cp1402 assignment - netw...
2024-12-24
热点标签
mktg2509
csci 2600
38170
lng302
csse3010
phas3226
77938
arch1162
engn4536/engn6536
acx5903
comp151101
phl245
cse12
comp9312
stat3016/6016
phas0038
comp2140
6qqmb312
xjco3011
rest0005
ematm0051
5qqmn219
lubs5062m
eee8155
cege0100
eap033
artd1109
mat246
etc3430
ecmm462
mis102
inft6800
ddes9903
comp6521
comp9517
comp3331/9331
comp4337
comp6008
comp9414
bu.231.790.81
man00150m
csb352h
math1041
eengm4100
isys1002
08
6057cem
mktg3504
mthm036
mtrx1701
mth3241
eeee3086
cmp-7038b
cmp-7000a
ints4010
econ2151
infs5710
fins5516
fin3309
fins5510
gsoe9340
math2007
math2036
soee5010
mark3088
infs3605
elec9714
comp2271
ma214
comp2211
infs3604
600426
sit254
acct3091
bbt405
msin0116
com107/com113
mark5826
sit120
comp9021
eco2101
eeen40700
cs253
ece3114
ecmm447
chns3000
math377
itd102
comp9444
comp(2041|9044)
econ0060
econ7230
mgt001371
ecs-323
cs6250
mgdi60012
mdia2012
comm221001
comm5000
ma1008
engl642
econ241
com333
math367
mis201
nbs-7041x
meek16104
econ2003
comm1190
mbas902
comp-1027
dpst1091
comp7315
eppd1033
m06
ee3025
msci231
bb113/bbs1063
fc709
comp3425
comp9417
econ42915
cb9101
math1102e
chme0017
fc307
mkt60104
5522usst
litr1-uc6201.200
ee1102
cosc2803
math39512
omp9727
int2067/int5051
bsb151
mgt253
fc021
babs2202
mis2002s
phya21
18-213
cege0012
mdia1002
math38032
mech5125
07
cisc102
mgx3110
cs240
11175
fin3020s
eco3420
ictten622
comp9727
cpt111
de114102d
mgm320h5s
bafi1019
math21112
efim20036
mn-3503
fins5568
110.807
bcpm000028
info6030
bma0092
bcpm0054
math20212
ce335
cs365
cenv6141
ftec5580
math2010
ec3450
comm1170
ecmt1010
csci-ua.0480-003
econ12-200
ib3960
ectb60h3f
cs247—assignment
tk3163
ics3u
ib3j80
comp20008
comp9334
eppd1063
acct2343
cct109
isys1055/3412
math350-real
math2014
eec180
stat141b
econ2101
msinm014/msing014/msing014b
fit2004
comp643
bu1002
cm2030
联系我们
- QQ: 9951568
© 2021
www.rj363.com
软件定制开发网!