首页
网站开发
桌面应用
管理软件
微信开发
App开发
嵌入式软件
工具软件
数据采集与分析
其他
首页
>
> 详细
CS 2550代做、代写SQL设计编程
项目预算:
开发周期:
发布时间:
要求地区:
CS 2550 – Principles of Database Systems (Spring 2024)
Dept. of Computer Science, University of Pittsburgh
Assignment #4: Query Processing & Optimization
Release: April 10, 2024 Due: 8:00PM, April 22, 2024
Goal
The goal of this assignment is to better understand the query evaluation process.
Description
The following is a fragment of the university database schema.
Employee (EmployeeID, First, Last, Gender, DOB, Address, Phone, SNO, Salary)
PK(EmployeeID)
FK(SNO) --> Studio(StudioNum)
Studio (StudioNum, StudioName, Manager, Budget)
PK(StudioNum)
FK(Manager) --> Employee(EmployeeID)
Movie (movieID, producedBy, title, Budget, filmedAt)
PK(movieID)
FK(producedBy) --> Studio(StudioNum)
Consider four possible organizations of the tables Employee(E)-Studio(S)-Movie(M):
1. Tables E, S and M are heap files & no access methods exist on any of them
2. Tables E and S are sorted files and M is a heap file & no access methods exist on any of them
3. Tables E, S and M are heap files & access methods (hashing) exist only on M
4. Table E is a sorted file and tables S and M are heap files & access methods exist on E and
M, one of which is hash and the other is index
Further assume the following statistics:
Available Cache Memory (CM) to be 22 pages.
Attributes belonging to the same table all have the same average size.
When using hash join, the smaller record will be the partitioning part.
The distribution of values for the attribute filmedAt in the table Movie is: 50% ’PGH’, 30%
’PHI’, and 20% ’NYC’.
Movie: r = 500, bfr = 5, BP rj = 100.
Studio: r = 250, bfr = 5, BDep = 50.
Employee: r = 1250, bfr = 5, BEmp = 250.
Note that r is the total number of tuples in a table, bfr is the blocking-factor, and B is the
total number of blocks of a table.
Questions [100 points]
Q1 [20 points] Produce the heuristic query evaluation tree of the following SQL statement assuming no access structures available, and describe in details how the evaluation of the query would
be:
SELECT S.StudioName, COUNT(M.movieID), SUM(M.Budget)
FROM EMPLOYEE AS E, Studio AS S, Movie AS M
WHERE M.producedBy = S.StudioNum AND E.SNO = S.StudioNum
GROUP BY S.StudioName
HAVING COUNT(E.EmployeeID) < 15;
State any additional assumptions. (Hint: some operators can be combined into a single algorithm).
Q2 [80 points] Consider the query evaluation tree as discussed in class of the following SQL
statement.
SELECT M.movieID, M.producedBy, E.First, E.Last, E.Gender
FROM Employee AS E, Studio AS S, Movie AS M
WHERE M.producedBy = S.StudioNum AND S.Manager = E.EmployeeID
AND M.filmedAt=‘PGH’;
Based on your pittID, you have two database organizations assigned to you from the above organizations in order to answer this question. For those two organizations, identify sub trees that
represent groups of operations which can be executed by a single algorithm. For each such sub tree,
there are potentially multiple methods that can be combined to implement it as a single algorithm.
Please provide the following:
The description of one such implementation (steps & data structures) out of all possible ones
for each of the above cases.
The I/O cost of your implementation at each level.
Compute the total I/O cost.
You are asked to answer the question for two database organizations, those are based on your
pittID, as follows:
ddh32, tiw81, yiy161, dhb51, yul251, sml153, nia135, dtk28:
You are required to do the first and second organizations only.
mas937, yux85, anp407, shk148, nat134, aba166, mod53, jeb386:
You are required to do the first and third organizations only.
aym50, bsp22, yuw328, shy158, btl26, shp184, jah292, tbt8:
You are required to do the first and fourth organizations only.
What & How to submit
You are required to submit exactly one PDF file under your pitt user name (e.g.,
pitt01.pdf). In addition to providing the answer, you are expected to: include your
name and pitt ID at the top of the PDF file.
After preparing your solution, submit your file (i.e., the prepared PDF) that contains
your solution by going to the class’ Gradescope by either navigating to the Gradescope
Homepage and selecting the course CS 2550 from the Course Dashboard or by clicking
the Gradescope Navigation option under our course Canvas page.
You must submit your assignment before the due date (8:00 PM, Apr. 22, 2024).
There are no late submissions.
Note that you are required to use a graph tool (such as MS-Word, MS Powerpoint, MS
Visio, idraw, draw.io, etc.) to generate your diagrams and the text that explain them.
Handwritten/Hand-drawn diagrams and/or text will not be accepted/graded
and will receive a zero. Hand-written and digitized/scanned images will
receive a zero (including scanned, photos, or electronically drawn using a
smart pen submissions).
Academic Honesty
The work in this assignment is to be done independently. Discussions with other students on
the assignment should be limited to understanding the statement of the problem. Cheating
in any way, including giving your work to someone else will result in an F for the course and
a report to the appropriate University authority.
软件开发、广告设计客服
QQ:99515681
邮箱:99515681@qq.com
工作时间:8:00-23:00
微信:codinghelp
热点项目
更多
代做 program、代写 c++设计程...
2024-12-23
comp2012j 代写、代做 java 设...
2024-12-23
代做 data 编程、代写 python/...
2024-12-23
代做en.553.413-613 applied s...
2024-12-23
代做steady-state analvsis代做...
2024-12-23
代写photo essay of a deciduo...
2024-12-23
代写gpa analyzer调试c/c++语言
2024-12-23
代做comp 330 (fall 2024): as...
2024-12-23
代写pstat 160a fall 2024 - a...
2024-12-23
代做pstat 160a: stochastic p...
2024-12-23
代做7ssgn110 environmental d...
2024-12-23
代做compsci 4039 programming...
2024-12-23
代做lab exercise 8: dictiona...
2024-12-23
热点标签
mktg2509
csci 2600
38170
lng302
csse3010
phas3226
77938
arch1162
engn4536/engn6536
acx5903
comp151101
phl245
cse12
comp9312
stat3016/6016
phas0038
comp2140
6qqmb312
xjco3011
rest0005
ematm0051
5qqmn219
lubs5062m
eee8155
cege0100
eap033
artd1109
mat246
etc3430
ecmm462
mis102
inft6800
ddes9903
comp6521
comp9517
comp3331/9331
comp4337
comp6008
comp9414
bu.231.790.81
man00150m
csb352h
math1041
eengm4100
isys1002
08
6057cem
mktg3504
mthm036
mtrx1701
mth3241
eeee3086
cmp-7038b
cmp-7000a
ints4010
econ2151
infs5710
fins5516
fin3309
fins5510
gsoe9340
math2007
math2036
soee5010
mark3088
infs3605
elec9714
comp2271
ma214
comp2211
infs3604
600426
sit254
acct3091
bbt405
msin0116
com107/com113
mark5826
sit120
comp9021
eco2101
eeen40700
cs253
ece3114
ecmm447
chns3000
math377
itd102
comp9444
comp(2041|9044)
econ0060
econ7230
mgt001371
ecs-323
cs6250
mgdi60012
mdia2012
comm221001
comm5000
ma1008
engl642
econ241
com333
math367
mis201
nbs-7041x
meek16104
econ2003
comm1190
mbas902
comp-1027
dpst1091
comp7315
eppd1033
m06
ee3025
msci231
bb113/bbs1063
fc709
comp3425
comp9417
econ42915
cb9101
math1102e
chme0017
fc307
mkt60104
5522usst
litr1-uc6201.200
ee1102
cosc2803
math39512
omp9727
int2067/int5051
bsb151
mgt253
fc021
babs2202
mis2002s
phya21
18-213
cege0012
mdia1002
math38032
mech5125
07
cisc102
mgx3110
cs240
11175
fin3020s
eco3420
ictten622
comp9727
cpt111
de114102d
mgm320h5s
bafi1019
math21112
efim20036
mn-3503
fins5568
110.807
bcpm000028
info6030
bma0092
bcpm0054
math20212
ce335
cs365
cenv6141
ftec5580
math2010
ec3450
comm1170
ecmt1010
csci-ua.0480-003
econ12-200
ib3960
ectb60h3f
cs247—assignment
tk3163
ics3u
ib3j80
comp20008
comp9334
eppd1063
acct2343
cct109
isys1055/3412
math350-real
math2014
eec180
stat141b
econ2101
msinm014/msing014/msing014b
fit2004
comp643
bu1002
cm2030
联系我们
- QQ: 9951568
© 2021
www.rj363.com
软件定制开发网!