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代写ECE 463、代做C++, Java编程

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NC State University
Department of Electrical and Computer Engineering
ECE 463/563 (Prof. Rotenberg)
Project #1: Cache Design, Memory Hierarchy Design (Version 1.0)
Due: Fri., Oct. 13, 11:59 PM
1. Preliminary Information
1.1. Academic integrity
• Academic integrity:
o Source code: Each student must design and write their source code alone. They must do
this (design and write their source code) without the assistance of any other person in
ECE 463/563 or not in ECE 463/563. They must do this (design and write their source
code) without searching the web for past semesters’ projects and without searching the
web for source code with similar goals (e.g., modeling computer architecture components
such as caches, predictors, pipelines, etc.), which is strictly forbidden. They must do this
(design and write their source code) without looking at anyone else’s source code,
without obtaining electronic or printed copies of anyone else’s source code, etc. Use of
ChatGPT or other generative AI tools is prohibited.
o Explicit debugging: With respect to “explicit debugging” as part of the coding process
(e.g., using a debugger, inspecting code for bugs, inserting prints in the code, iteratively
applying fixes, etc.), each student must explicitly debug their code without the assistance
of any other person in ECE 463/563 or not in ECE 463/563.
o Report: Each student must run their own experiments, collect and process their own
data, and write their own report. Plagiarism (lifting text, graphs, illustrations, etc., from
someone else, whether one adjusts the originals or not) is prohibited. Using someone
else’s data (in raw form and/or graph form) is prohibited. Fabricating data is prohibited.
o Sanctions: The sanctions for violating the academic integrity policy are (1) a score of 0
on the project and (2) academic integrity probation for a first-time offense or suspension
for a subsequent offense (the latter sanctions are administered by the Office of Student
Conduct). Note that, when it comes to academic integrity violations, both the giver and
receiver of aid are responsible and both are sanctioned. Please see the following RAIV
form which has links to various policies and procedures and gives a sense of how
academic integrity violations are confronted, documented, and sanctioned: RAIV form.
o Enforcement: The TAs will scan source code (from current and past semesters) through
tools available to us for detecting cheating. The outputs from these tools, combined with
in-depth manual analysis of these outputs, will be the basis for investigating suspected
academic integrity violations. TAs will identify suspected plagiarism and/or data
fabrication and these cases will be investigated.
• Reasonable assistance: If a student has any doubts or questions, or if a student is stumped by
a bug, the student is encouraged to seek assistance using both of the following channels.
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o Students may receive assistance from the TAs and instructor.
o Students are encouraged to post their doubts, questions, and obstacles, on the Moodle
message board for this project. The instructor and TA will moderate the message board
to ensure that reasonable assistance is provided to the student. Other students are
encouraged to contribute answers so long as no source code is posted.
* An example of reasonable assistance via the message board: Student A: “I’m encountering the
following problem: I’m getting fewer writebacks from L2 to main memory than the validation
runs. Has anyone else encountered something like this?” Student B: “Yes, I encountered
something similar, and you might want to take a look at how you are doing XYZ because the
problem has to do with such-and-such.”
* Another example of a reasonable exchange: Student A: “I’m unsure how to split the address
into tag and index, and how to discard the block offset bits. I’ve successfully computed the # bits
for each but I am stuck on how to manipulate the address in C/C++. Do you have any advice?”
Instructor/TA/Student B: “We suggest you use an unsigned integer type for the address and use
bitwise manipulation, such as ANDs (&), ORs (|), and left/right shifts (<<. >>) to extract values
from the unsigned integer, the same as one would do in Verilog.”
* Another example of a reasonable exchange: Student A: “I’m unsure how to dynamically
allocate memory, such as dynamically allocating a 1D array of structs/classes or (more
appropriately for a cache) a 2D array of structs/classes. Can you point me to some references on
this?” Instructor/TA/Student B: “Sure, here is a web site or reference book that discusses
dynamic memory allocation including 1D and 2D arrays.”
• The intent of the academic integrity policy is to ensure students code and explicitly
debug their code by themselves. It is NOT our intent to stifle robust, interesting, and
insightful discussion and Q&A that is helpful for students (and the instructor and TA)
to learn together. We also would like to help students get past bugs by offering advice
on where they may be doing things incorrectly, or where they are making incorrect
assumptions, etc., from an academic and conceptual standpoint.
1.2. Reduced project scope for ECE 463 students
The project scope is reduced but still substantial for ECE 463 students, as detailed in this
specification.
1.3. Programming languages for this project
You must implement your project using the C, C++, or Java languages, for two reasons. First,
these languages are preferred for computer architecture performance modeling. Second, our
Gradescope autograder only supports compilation of these languages.
1.4. Responsibility for self-grading your project via Gradescope
You will submit, validate, and SELF-GRADE your project via Gradescope; the TAs will only
manually grade the report. While you are developing your simulator, you are required to
frequently check via Gradescope that your code compiles, runs, and gives expected outputs with
respect to your current progress. This is necessary to resolve porting issues in a timely fashion
(i.e., well before the deadline), caused by different compiler versions in your programming
environment and the Gradescope backend. This is also necessary to resolve non-compliance
issues (i.e., how you specify the simulator’s command-line arguments, how you format the
simulator’s outputs, etc.) in a timely fashion (i.e., well before the deadline).
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2. Project Description
In this project, you will implement a flexible cache and memory hierarchy simulator and use it to
compare the performance, area, and energy of different memory hierarchy configurations, using
a subset of the SPEC 2006 benchmark suite, SPEC 2017 benchmark suite, and/or
microbenchmarks.
3. Specification of Memory Hierarchy
Design a generic cache module that can be used at any level in a memory hierarchy. For
example, this cache module can be “instantiated” as an L1 cache, an L2 cache, an L3 cache, and
so on. Since it can be used at any level of the memory hierarchy, it will be referred to generically
as CACHE throughout this specification.
3.1. Configurable parameters
CACHE should be configurable in terms of supporting any cache size, associativity, and block
size, specified at the beginning of simulation:
o SIZE: Total bytes of data storage.
o ASSOC: The associativity of the cache. (ASSOC = 1 is a direct-mapped cache. ASSOC
= # blocks in the cache = SIZE/BLOCKSIZE is a fully-associative cache.)
o BLOCKSIZE: The number of bytes in a block.
There are a few constraints on the above parameters: 1) BLOCKSIZE is a power of two and 2)
the number of sets is a power of two. Note that ASSOC (and, therefore, SIZE) need not be a
power of two. As you know, the number of sets is determined by the following equation:
ASSOC BLOCKSIZE
SIZE
sets
×
# =
3.2. Replacement policy
CACHE should use the LRU (least-recently-used) replacement policy.
3.3. Write policy
CACHE should use the WBWA (write-back + write-allocate) write policy.
o Write-allocate: A write that misses in CACHE will cause a block to be allocated in
CACHE. Therefore, both write misses and read misses cause blocks to be allocated in
CACHE.
o Write-back: A write updates the corresponding block in CACHE, making the block dirty.
It does not update the next level in the memory hierarchy (next level of cache or
memory). If a dirty block is evicted from CACHE, a writeback (i.e., a write of the entire
block) will be sent to the next level in the memory hierarchy.
3.4. Allocating a block: Sending requests to next level in the memory
hierarchy
Your simulator must be capable of modeling one or more instances of CACHE to form an
overall memory hierarchy, as shown in Figure 1.
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CACHE receives a read or write request from whatever is above it in the memory hierarchy
(either the CPU or another cache). The only situation where CACHE must interact with the next
level below it (either another CACHE or main memory) is when the read or write request misses
in CACHE. When the read or write request misses in CACHE, CACHE must “allocate” the
requested block so that the read or write can be performed.
Thus, let us think in terms of allocating a requested block X in CACHE. The allocation of
requested block X is actually a two-step process. The two steps must be performed in the
following order.
1. Make space for the requested block X. If there is at least one invalid block in the set, then
there is already space for the requested block X and no further action is required (go to
step 2). On the other hand, if all blocks in the set are valid, then a victim block V must be
singled out for eviction, according to the replacement policy (Section 3.2). If this victim
block V is dirty, then a write of the victim block V must be issued to the next level of the
memory hierarchy.
2. Bring in the requested block X. Issue a read of the requested block X to the next level of
the memory hierarchy and put the requested block X in the appropriate place in the set (as
per step 1).
To summarize, when allocating a block, CACHE issues a write request (only if there is a victim
block and it is dirty) followed by a read request, both to the next level of the memory hierarchy.
Note that each of these two requests could themselves miss in the next level of the memory
hierarchy (if the next level is another CACHE), causing a cascade of requests in subsequent
levels. Fortunately, you only need to correctly implement the two steps for an allocation locally
within CACHE. If an allocation is correctly implemented locally (steps 1 and 2, above), the
memory hierarchy as a whole will automatically handle cascaded requests globally.
3.5. Updating state
After servicing a read or write request, whether the corresponding block was in the cache already
(hit) or had just been allocated (miss), remember to update other state. This state includes LRU
counters affiliated with the set as well as the valid and dirty bits affiliated with the requested
block.
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Read or Write Request
from CPU
Read or Write Request
Read or Write Request
Read or Write Request
Main Memory
CACHE
CACHE
Figure 1. Your simulator must be capable of modeling one or more instances of CACHE to form an overall
memory hierarchy.
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4. ECE 563 Students: Augment CACHE with Stream-Buffer
Prefetching
Students enrolled in ECE 563 must additionally augment CACHE with a prefetch unit. The
prefetch unit implements Stream Buffers.
In this project, consider the prefetch unit to be an extension implemented within CACHE. This
preserves the clean abstraction of one or more instances of CACHE interacting in an overall
memory hierarchy (see Figure 1), where each CACHE may have a prefetch unit within it.
4.1. CACHE should support a configurable prefetch unit
Your generic implementation of CACHE should support a configurable prefetch unit as follows.
The prefetch unit has N Stream Buffers. Each Stream Buffer contains M memory blocks. Both N
and M should be configurable. Setting N=0 disables the prefetch unit.
4.2. Operation of a single Stream Buffer
A Stream Buffer is a simple queue that is capable of holding M consecutive memory blocks.
A Stream Buffer has a single valid bit that indicates the validity of the buffer as a whole. If its
valid bit is 0, it means the Stream Buffer is empty and doesn’t contain a prefetch stream. If its
valid bit is 1, it means the Stream Buffer is full and contains a prefetch stream (M consecutive
memory blocks).
When CACHE receives a read or write request for block X, both CACHE and its Stream Buffer
are checked for a hit. Note that all Stream Buffer entries, not just the first entry (as in the original
Stream Buffer paper), are searched for block X. There are four possible scenarios:
1. Scenario #1 (create a new prefetch stream): Requested block X misses in CACHE
and misses in Stream Buffer: Handle the miss in CACHE as usual (see Section 3.4). In
addition to fetching the requested block X into CACHE, prefetch the next M consecutive
memory blocks into the Stream Buffer. That is, prefetch memory blocks X+1, X+2, …,
X+M into the Stream Buffer, thereby replacing the entire contents of the Stream Buffer.
Note that prefetches are implemented by issuing read requests to the next level in the
memory hierarchy.1 Also note that replacing the contents of the Stream Buffer does not
involve any writebacks from the Stream Buffer: this will be explained in Section 4.4.
2. Scenario #2 (benefit from and continue a prefetch stream): Requested block X
misses in CACHE and hits in the Stream Buffer: Perform an allocation in CACHE as
follows. First, make space in CACHE for the requested block X (as described in Section
3.4). Second, instead of fetching the requested block X from the next level in the memory
hierarchy, copy the requested block X from the Stream Buffer into CACHE (since the
1 For accurate performance accounting using the Average Access Time (AAT) expression, you will need to convey
to the next level in the memory hierarchy that these read requests are prefetches. This will enable the next level in
the memory hierarchy to distinguish between 1) its read misses that originated from normal read requests versus 2)
its read misses that originated from prefetch read requests. Note that this is only needed for accurate performance
accounting.
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Stream Buffer contains the requested block X, in this scenario). Next, manage the Stream
Buffer as illustrated in Figure 2. Notice in the “before” picture, the fourth entry of the
Stream Buffer hit (it contained the requested block X). As shown in the “after” picture,
all blocks before and including block X (X-3, X-2, X-1, X) are removed from the Stream
Buffer, the blocks after block X (X+1, X+2) are “shifted up”, and the newly freed entries
are refilled by prefetching the next consecutive blocks (issue prefetches of blocks X+3,
X+4, X+5, X+6). A non-shifting circular buffer implementation, based on a head pointer
that points to the least block address in the prefetch stream, is more efficient in real
hardware and in software simulators, and is illustrated in Figure 3.
3. Scenario #3 (do nothing): Requested block X hits in CACHE and misses in the
Stream Buffer: In this case, nothing happens with respect to the Stream Buffer.
4. Scenario #4 (continue prefetch stream to stay in sync with demand stream):
Requested block X hits in CACHE and hits in the Stream Buffer: Manage the Stream
Buffer identically to Scenario #2. The only difference is that the requested block X hit in
CACHE, so there is no transfer from Stream Buffer to CACHE.
X-3
X-2
X-1
X
X+1
X+2
V (valid) = 1
before
X-3
X-2
X-1
X
X+1
X+2
V (valid) = 1
after
hit
X+1
X+2
X+1
X+2
X+3
X+4
X+5
X+6
Figure 2. Managing the Stream Buffer when there is a hit in the Stream Buffer (scenarios #2 and #4).
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X-3
X-2
X-1
X
X+1
X+2
V (valid) = 1
before
X-3
X-2
X-1
X
X+1
X+2
V (valid) = 1
after
hit
X+1
X+2
X+3
X+4
X+5
X+6
X+1
X+2
head 
head 
Figure 3. A non-shifting circular buffer implementation is more efficient in hardware and in software
simulators.
4.3. Multiple Stream Buffers
The operation of a single Stream Buffer, described in the previous section, extends to multiple
Stream Buffers. The main difference is that all Stream Buffers are checked for a hit.
For Scenario #1 (request misses in CACHE and misses in all Stream Buffers), one of the Stream
Buffers must be chosen for the new prefetch stream: select the least-recently-used Stream Buffer,
i.e., apply the LRU policy to the Stream Buffers as a whole. When a new stream is prefetched
into a particular Stream Buffer (Scenario #1), or a particular Stream Buffer supplies a requested
block to CACHE (Scenario #2), or we are keeping a Stream Buffer in sync (Scenario #4), that
Stream Buffer becomes the most-recently-used buffer.
Policy for multiple Stream Buffer hits:
It is possible for two or more Stream Buffers to have some blocks in common (redundancy). For
example, suppose all Stream Buffers are initially invalid and CACHE is empty; the CPU
requests block X which creates the prefetch stream X+1 to X+6 in a first Stream Buffer (assume
M=6); and then the CPU requests block X-2 which creates the prefetch stream X-1 to X+4 in a
second Stream Buffer; thus, after these initial two misses, the Stream Buffers have X+1 to X+4
in common. Other scenarios create redundancy as well, such as one continuing prefetch stream
reaching the start of another prefetch stream.
Redundancy means that a given request may hit in multiple Stream Buffers. Managing multiple
Stream Buffers as in Figure 2, for the same hit, results in redundant prefetches because the
multiple Stream Buffers will all try to continue their overlapping streams. A simple solution is
to only consider the hit to the most-recently-used Stream Buffer among those that hit and
ignore the other hits. From a simulator standpoint, this could mean (for example) searching
Stream Buffers for a hit in recency order, and stopping at the first hit. Only that Stream Buffer is
managed as shown in Figure 2, i.e., only that Stream Buffer continues its prefetch stream.
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4.4. Assume Stream Buffers are updated by writebacks with no effect
on recency (no explicit modeling required in your simulator)
A Stream Buffer never contains dirty blocks, that is, it never contains a block whose content
differs from the same block in the next level of the memory hierarchy. The benefit of this design
is that replacing the contents of the Stream Buffer will never require writebacks from the Stream
Buffer.
In this section, we discuss a Stream Buffer complication that we will handle conceptually. The
problem and solution are only discussed out of academic interest. The solution does not require
any explicit support in the simulator.
Consider that a dirty copy of block Y may exist in CACHE while a clean copy of block Y exists
in a Stream Buffer. Here is a simple example of how we can get into this situation (assume M=6
for the example):
• Write request to block Y misses in CACHE. Block Y is allocated in CACHE, write is
performed, and block Y is dirty in CACHE. Prefetch stream Y+1 to Y+6 is created in a
first Stream Buffer, although this is not germane for this example.
• Then, a request to block Y-2 misses in CACHE. Prefetch stream Y-1 to Y+4 is created in
a second Stream Buffer. Thus, at this point, CACHE has a dirty copy of block Y and the
second Stream Buffer has a clean copy of block Y.
Now, suppose CACHE evicts its dirty copy of block Y (e.g., it is replaced by a missed block Z)
before referencing it again (fyi: referencing it as a hit might wipe it from the Stream Buffer to
keep the latter’s prefetch stream in sync with demand references, as per scenario #4). Stale block
Y still exists in the Stream Buffer which could lead to incorrect operation in the future, namely,
when the CPU requests block Y again and hits on the stale copy in the Stream Buffer.
We will assume a solution that does NOT require any code in your simulator. When a dirty block
Y is evicted from CACHE (i.e., when there is a writeback), any Stream Buffers that contain
block Y update their copy of block Y. In this way, a Stream Buffer’s copy of block Y will
remain clean and up to date with respect to the next level, since the writeback is performed not
only in the next level but also in the Stream Buffer. In addition, let us also assume that this
operation does NOT update recency among Stream Buffers. Therefore, the only effect is
updating data, and your simulator does not model data.
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5. Memory Hierarchies to be Explored in this Project
While Figure 1 illustrates an arbitrary memory hierarchy, you will only study the memory
hierarchy configurations shown in Figure 4 (ECE 463) and Figure 5 (ECE 563). Also, these are
the only configurations that Gradescope will test.
For this project, all CACHEs in the memory hierarchy will have the same BLOCKSIZE.
Level-1 (L1)
Read or Write Request
from CPU
Read or Write Request
Level-2 (L2)
Read or Write Request
Main Memory
CACHE
CACHE
Level-1 (L1)
Read or Write Request
from CPU
Read or Write Request
Main Memory
CACHE
Figure 4. ECE 463: Two configurations to be studied.
Level-1 (L1)
Read or Write Request
from CPU
Read or Write Request
Level-2 (L2)
Read or Write Request
Main Memory
CACHE
CACHE
Level-1 (L1)
Read or Write Request
from CPU
Read or Write Request
Main Memory
CACHE
Level-1 (L1)
Read or Write Request
from CPU
Read or Write Request
Level-2 (L2)
+
Prefetch Unit
Read or Write Request
Main Memory
CACHE
CACHE
Level-1 (L1)
+
Prefetch Unit
Read or Write Request
from CPU
Read or Write Request
Main Memory
CACHE
Figure 5. ECE 563: Four configurations to be studied.
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6. Inputs to Simulator
6.1. Traces
The simulator reads a trace file in the following format:
r|w
r|w
...
“r” (read) indicates a load and “w” (write) indicates a store from the processor.
Example:
r ffe04540
r ffe04544
w 0eff2340
r ffe04548
...
Traces are posted on the Moodle website.
NOTE:
All addresses are 32 bits. When expressed in hexadecimal format (hex), an address is 8 hex digits
as shown in the example trace above. In the actual trace files, you may notice some addresses are
comprised of fewer than 8 hex digits: this is because there are leading 0’s which are not
explicitly shown. For example, an address “ffff” is really “0000ffff”, because all addresses
are 32 bits, i.e., 8 nibbles.
6.2. Command-line arguments to the simulator
The simulator executable built by your Makefile must be named “sim” (the Makefile is discussed
in Section 8).
Your simulator must accept exactly 8 command-line arguments in the following order:
sim




o BLOCKSIZE: Positive integer. Block size in bytes. (Same block size for all
caches in the memory hierarchy.)
o L1_SIZE: Positive integer. L1 cache size in bytes.
o L1_ASSOC: Positive integer. L1 set-associativity (1 is direct-mapped,
L1_SIZE/BLOCKSIZE is fully-associative).
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o L2_SIZE: Positive integer. L2 cache size in bytes. L2_SIZE = 0 signifies
that there is no L2 cache.
o L2_ASSOC: Positive integer. L2 set-associativity (1 is direct-mapped,
L2_SIZE/BLOCKSIZE is fully-associative).
o PREF_N: Positive integer. Number of Stream Buffers in the L1 prefetch unit
(if there is no L2) or the L2 prefetch unit (if there is an L2). PREF_N = 0
disables the prefetch unit.
o PREF_M: Positive integer. Number of memory blocks in each Stream Buffer
in the L1 prefetch unit (if there is no L2) or the L2 prefetch unit (if there is an
L2).
o trace_file: Character string. Full name of trace file including any
extensions.
Example: 8KB 4-way set-associative L1 cache with 32B block size, 256KB 8-
way set-associative L2 cache with 32B block size, L2 prefetch unit has 3 stream
buffers with 10 blocks each, gcc trace:
sim 32 8192 4 262144 8 3 10 gcc_trace.txt
Some additional points:
• You may assume that only valid arguments will be applied to your simulator by
Gradescope. Thus, while it is good practice for programmers to check arguments (e.g.,
check that the specified trace file exists and can be opened; e.g., check that SIZE,
ASSOC, and BLOCKSIZE lead to a feasible cache; e.g., check that the correct number of
arguments are passed in), you are NOT required to do so.
• Although ECE 463 students do not implement prefetching, they must still parse the
prefetching-related arguments the same as ECE 563 students. ECE 463 students may
assume that, for their projects, Gradescope will always specify “0 0” for arguments
PREF_N and PREF_M.
• ECE 563 students may notice that, for this project, there is only one pair of prefetcher
configuration arguments (PREF_N, PREF_M) and that these are applied only to the last
level of cache in the memory hierarchy. This is consistent with Figure 5.
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7. Outputs from Simulator
Your simulator should output the following:
(See Section 8 regarding the formatting of these outputs and validating your simulator.)
1. Memory hierarchy configuration and trace filename.
2. The final contents of all caches and their stream buffers (if applicable). For cache contents,
blocks within a set must be printed out from most-recently-used to least-recently-used. Omit (do
not print) invalid blocks within a set, if there are any. If a given set has no valid blocks, omit (do
not print) that set. Stream buffers (if present) must be printed out from most-recently-used to
least-recently-used, and only valid stream buffers should be printed out.
3. The following measurements: (note that “miss” means neither the cache nor its stream buffers
hit)
a. number of L1 reads
b. number of L1 read misses, excluding L1 read misses that hit in the stream buffers if L1
prefetch unit is enabled
c. number of L1 writes
d. number of L1 write misses, excluding L1 write misses that hit in the stream buffers if L1
prefetch unit is enabled
e. L1 miss rate = MRL1 = (L1 read misses + L1 write misses)/(L1 reads + L1 writes)
f. number of writebacks from L1 to next level
g. number of L1 prefetches (prefetch requests from L1 to next level, if prefetch unit is enabled)
h. number of L2 reads that did not originate from L1 prefetches (should match b+d: L1 read
misses + L1 write misses)
i. number of L2 read misses that did not originate from L1 prefetches, excluding such L2 read
misses that hit in the stream buffers if L2 prefetch unit is enabled
j. number of L2 reads that originated from L1 prefetches (should match g: L1 prefetches)
† SEE IMPORTANT NOTE BELOW.
k. number of L2 read misses that originated from L1 prefetches, excluding such L2 read misses
that hit in the stream buffers if L2 prefetch unit is enabled
† SEE IMPORTANT NOTE BELOW.
l. number of L2 writes (should match f: number of writebacks from L1)
m. number of L2 write misses, excluding L2 write misses that hit in the stream buffers if L2
prefetch unit is enabled
n. L2 miss rate (from standpoint of stalling the CPU) = MRL2 = (item i)/(item h)
o. number of writebacks from L2 to memory
p. number of L2 prefetches (prefetch requests from L2 to next level, if prefetch unit is enabled)
q. total memory traffic = number of blocks transferred to/from memory
(with L2, should match i+k+m+o+p:
all L2 read misses + L2 write misses + writebacks from L2 + L2 prefetches)
(without L2, should match b+d+f+g:
L1 read misses + L1 write misses + writebacks from L1 + L1 prefetches)
† For this project, as shown in Figure 5 for ECE 563 students, prefetching is only tested and
explored in the last-level cache of the memory hierarchy. This means that measurements j and k,
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above, should always be 0 because the L1 will not issue prefetch requests to the L2. Nonetheless,
a well-done implementation of a generic CACHE will distinguish incoming demand read
requests from incoming prefetch read requests, even though in this project the distinction will
not be exercised.
Note for ECE 463 students: Just assume and print 0 for any prefetch-specific
measurement. These are: g, j, k, p.
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8. Submit, Validate, and Self-Grade with Gradescope
Sample simulation outputs are provided on the Moodle site. These are called “validation runs”.
Refer to the validation runs to see how to format the outputs of your simulator.
You must submit, validate, and self-grade2 your project using Gradescope. Here is how
Gradescope (1) receives your project (zip file), (2) compiles your simulator (Makefile), and (3)
runs and checks your simulator (arguments, print-to-console requirement, and “diff -iw”):
1. How Gradescope receives your project: zip file. While you are developing your simulator,
you may continuously submit new zip files to Gradescope containing the latest version of your
project. The latest submission is the one that is considered for your grade. Gradescope will
accept a zip file consisting of three things: your source code, a Makefile to compile your source
code, and your project report. In the early stages of your project, before creating the report, your
zip file will have only source code and a Makefile. Once the report is completed, your zip file
will contain everything.
1. Report (included in the zip file once available): The report must be a PDF file named
“report.pdf” located at the top level of the zip file, because that is what Gradescope
looks for when checking completeness of the submission. The report must include the
following: See Section 9 and the report template in Moodle for the required contents
of the report.
• Makefile: The Makefile must be at the top level of the zip file, because Gradescope
runs “make” with the expectation that the Makefile is at the top level.
• Source code: Whether your source code is at the top level of the zip file or in
directories below the top level, your Makefile must be designed to compile your
source code, accordingly.
2. How Gradescope compiles your simulator: Makefile. Along with your source code, you
must provide a Makefile that automatically compiles the simulator. This Makefile must create a
simulator named “sim”. An example Makefile is posted on the Moodle site, which you can copy
and modify for your needs.
3. How Gradescope runs and checks your simulator: arguments, print-to-console
requirement, “diff -iw”, and timeout.
• Your simulator executable (created by your Makefile) must be named “sim” and take
command-line arguments in the manner specified in Section 6.2, because Gradescope
assumes these things.
• Your simulator must print outputs to the console (i.e., to the screen), because Gradescope
assumes this.
• Your output must match the validation runs both numerically and in terms of formatting,
because Gradescope runs “diff -iw” to compare your output with the correct output. The -
iw flags tell “diff” to treat upper-case and lower-case as equivalent and to ignore the
amount of whitespace between words. Therefore, you do not need to worry about the
2 The mystery runs component of your grade will not be published until we release it. The report will be manually
graded by the TAs.
16
exact number of spaces or tabs as long as there is some whitespace where the validation
runs have whitespace. Note, however, that extra or missi
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