首页
网站开发
桌面应用
管理软件
微信开发
App开发
嵌入式软件
工具软件
数据采集与分析
其他
首页
>
> 详细
CS3214代做、c/c++编程设计代写
项目预算:
开发周期:
发布时间:
要求地区:
CS3214 Fall 2023 Exercise 2
Due: See website for due date.
What to submit: Upload a tar archive that contains a text file answers.txt with your
answers for the questions not requiring code, as well as individual files for those that do,
as listed below.
This exercise is intended to reinforce the content of the lectures related to linking using
small examples.
As some answers are specific to our current environment, you must again do this exercise
on our rlogin cluster.
Our verification system will reject your submission if any of the required files are not in
your submission. If you want to submit for a partial credit, you still need to include all
the above files.
1
CS3214 Fall 2023 Exercise 2
1. Building Software
A common task is to use the compiler, linker, and surrounding build systems to build
large pieces of software. In this part, you are asked to build a piece of software and
observe a typical build process. Your answers will be specific to the version of the GCC
tool chain installed on rlogin this semester.
1. Download the source code of Node.js 18.18.0.
Read and follow the build instructions in BUILDING.md (note: Omit the ’make install’ step unless you specified a directory to which you have write access as the
installation directory (i.e., via the –prefix option to configure). The default installation destination directory is a system directory to which you do not have write
access. Hint: lookup the meaning of the -j flag to the make command before running make. Thanks to your engineering fees, make -j64 is ok to use on any rlogin
machine.
During the make process, identify the link command that produces the node executable and then answer the next two questions.
2. Find the -o flag, which specifies the directory in which the build process will leave
the ‘node’ executable post linking. Copy and paste the full path name appearing
after -o.
3. Find the location of the static library libuvwasi.a which is given in the link command line. How many .o files does this static library contain?
4. Which libraries are linked dynamically with the node executable (hint: use ldd and
ignore linux-vdso.so.1 and /lib64/ld-linux-x86-64.so.2)?
5. List the name of the 4 000th strong global text symbol found in the ‘node’ executable,
when considering them in alphabetical order. Hint: use a combination of nm, grep,
head, and tail.
6. How much space does the node executable take up on disk? (Use ls -l to find
out.)
7. The command size (without any arguments) gives you an estimate of how much
memory is needed if the executable were fully loaded into memory. Run size.
Roughly what fraction of the executable that is stored on disk would be loaded into
memory?
8. The command strip strips an executable of those parts that are not necessary to
run it. Run strip on the executable.
After stripping the executable, did the stored size of the executable on disk get
larger, smaller, or stay the same?
9. After stripping the executable in the previous step, did the amount of memory to
run the executable get larger, smaller, or stay the same?
2
CS3214 Fall 2023 Exercise 2
10. Almost half of the text size comes from a single .o module, out/Release/-
obj.target/node/gen/node_snapshot.o. Use nm on this file and pipe the
output through the c++filt program. Compare the output of this command to the
node.js API documentation at https://nodejs.org/dist/latest-v18.x/docs/api/.
Research what code and data is contained in this “snapshot” file and how it benefits
Node.js.
11. Last, but not least, do not forget to remove the source and build directory from your
rlogin file space. It takes up about 1.4GB of space.
2. Linking Cush
In this part of the exercise, you are asked to make small changes to the cush starter code
to induce linker errors and changes to the executable. To that end, you should clone a
fresh copy of the starter code with
git clone git@git.cs.vt.edu:cs3214-staff/cs3214-cush.git
cd cs3214-cush
(cd posix_spawn; make)
The 3 parts are independent and you should undo any changes you made for one part
before continuing to the next.
1. After changing 3 lines 1
in 2 files, cush rebuilds but the build fails with:2
cc -Wall -Werror -Wmissing-prototypes -I../posix_spawn -g -O2
-fsanitize=undefined -o cush -L../posix_spawn
cush.o shell-grammar.o list.o shell-ast.o termstate_management.o
utils.o signal_support.o -lspawn -ll -lreadline
/usr/bin/ld: termstate_management.o:/..../cs3214-cush/src/utils.h:11:
multiple definition of ‘job_list’;
cush.o:/..../cs3214-cush/src/utils.h:11: first defined here
/usr/bin/ld: utils.o:/..../cs3214-cush/src/utils.h:11:
multiple definition of ‘job_list’;
cush.o:/..../cs3214-cush/src/utils.h:11: first defined here
/usr/bin/ld: signal_support.o:/..../cs3214-cush/src/utils.h:11:
multiple definition of ‘job_list’;
cush.o:/..../cs3214-cush/src/utils.h:11: first defined here
collect2: error: ld returned 1 exit status
make: *** [Makefile:27: cush] Error 1
What lines were changed? Provide the output as a patch (which you can produce
via git diff.)
1This is not counting any empty/whitespace lines. Also, in your reproduction, the line numbers do not
need to match.
2
I introduced newlines for readability.
3
CS3214 Fall 2023 Exercise 2
2. After a single line change, the project builds but the following nm command shows
this:
$ nm cush | grep job_list
000000000041ffc0 B job_list
What line was changed and how? Provide the output as a patch.
3. After a single line change, the project build fails with
cc -Wall -Werror -Wmissing-prototypes -I../posix_spawn -g -O2
-fsanitize=undefined -o cush -L../posix_spawn cush.o
shell-grammar.o list.o shell-ast.o termstate_management.o utils.o
signal_support.o -lspawn -ll -lreadline
/usr/bin/ld: cush.o: in function ‘main’:
/..../cs3214-cush/src/cush.c:272: undefined reference to ‘job_list’
collect2: error: ld returned 1 exit status
make: *** [Makefile:27: cush] Error 1
What line was changed and how? Provide the output as a patch.
Remember to revert to the original starter code for each part!
3. Baking Pie
From past courses (CS 2505, CS 2506) you are familiar with threats that can affect vulnerable applications that contain buffer overflows. Some of the exploits that targeted such
applications made assumptions about the way in which they were built and run.
Consider the following program pie.c:
#include
#include
int data = 42;
int bss;
int
main()
{
int stack;
printf("my heap is at %p\n", malloc(4));
printf("my stack is at %p\n", &stack);
printf("my text is at %p\n", main);
printf("my data is at %p\n", &data);
4
CS3214 Fall 2023 Exercise 2
printf("my bss is at %p\n", &bss);
}
Compile and build two executables using the following commands:
gcc pie.c -o no.pie
gcc -fPIC -pie pie.c -o pie
Run ./no.pie two or more times, and run ./pie two or more times.
1. What does “PIE” stand for, and how did it change the environment when a program
built using this facility was loaded and run?
2. Which specific kind of attack technique is made more difficult when -fpie is used?
4. Link Time Optimization
Traditional separate compilation and linking has an important drawback: since the intermediate representation created by the compiler is no longer available at link time, potential interprocedural optimizations cannot be performed. For instance, the linker cannot
inline functions or replace calls to functions that produce constant results with their values.
Link Time Optimization (LTO) overcomes this drawback by preserving the compiler’s
intermediate representation and passing it along to the linker which can then perform
whole-program optimization across modules. Languages such as Rust use LTO to be able
to perform optimizations across the different source files that are part of a crate.
In this part of the exercise, you will be looking at how LTO works in a current compiler
(gcc 11.4.1).
Create or copy the following files lto1.c and lto2.c:
// declare externally defined function
// (this is not best practice - this declaration should be
// in a header file)
extern long math(long a);
#include
int
main() {
long h = math(3025);
printf("%d\n", h);
}
#include
// some not necessarily correct math function
extern long math(long a)
5
CS3214 Fall 2023 Exercise 2
{
long l = 0;
long h = a;
for (int i = 0; i < 18; i++) {
long m = l + (h - l) / 2;
if (a > m * m)
l = m + 1;
else
h = m;
}
return l;
}
Compile and build the two files using the following commands:
gcc -O3 -flto -c lto1.c lto2.c
gcc -O3 -flto lto1.o lto2.o -o lto
Then answer the following questions:
1. Use objdump -d to find the code for the main() in the final lto executable. Copy
and paste the body of main (the disassembled machine code)!
2. Now compile these programs without LTO like so:
gcc -O3 lto1.c lto2.c -o nolto
Use objdump -d nolto to look at the main function, and reproduce the assembly
code here.
Explain in your own words what the compiler and linker did when LTO was enabled and how this was possible using LTO but not when LTO was not being used.
6
软件开发、广告设计客服
QQ:99515681
邮箱:99515681@qq.com
工作时间:8:00-23:00
微信:codinghelp
热点项目
更多
urba6006代写、java/c++编程语...
2024-12-26
代做program、代写python编程语...
2024-12-26
代写dts207tc、sql编程语言代做
2024-12-25
cs209a代做、java程序设计代写
2024-12-25
cs305程序代做、代写python程序...
2024-12-25
代写csc1001、代做python设计程...
2024-12-24
代写practice test preparatio...
2024-12-24
代写bre2031 – environmental...
2024-12-24
代写ece5550: applied kalman ...
2024-12-24
代做conmgnt 7049 – measurem...
2024-12-24
代写ece3700j introduction to...
2024-12-24
代做adad9311 designing the e...
2024-12-24
代做comp5618 - applied cyber...
2024-12-24
热点标签
mktg2509
csci 2600
38170
lng302
csse3010
phas3226
77938
arch1162
engn4536/engn6536
acx5903
comp151101
phl245
cse12
comp9312
stat3016/6016
phas0038
comp2140
6qqmb312
xjco3011
rest0005
ematm0051
5qqmn219
lubs5062m
eee8155
cege0100
eap033
artd1109
mat246
etc3430
ecmm462
mis102
inft6800
ddes9903
comp6521
comp9517
comp3331/9331
comp4337
comp6008
comp9414
bu.231.790.81
man00150m
csb352h
math1041
eengm4100
isys1002
08
6057cem
mktg3504
mthm036
mtrx1701
mth3241
eeee3086
cmp-7038b
cmp-7000a
ints4010
econ2151
infs5710
fins5516
fin3309
fins5510
gsoe9340
math2007
math2036
soee5010
mark3088
infs3605
elec9714
comp2271
ma214
comp2211
infs3604
600426
sit254
acct3091
bbt405
msin0116
com107/com113
mark5826
sit120
comp9021
eco2101
eeen40700
cs253
ece3114
ecmm447
chns3000
math377
itd102
comp9444
comp(2041|9044)
econ0060
econ7230
mgt001371
ecs-323
cs6250
mgdi60012
mdia2012
comm221001
comm5000
ma1008
engl642
econ241
com333
math367
mis201
nbs-7041x
meek16104
econ2003
comm1190
mbas902
comp-1027
dpst1091
comp7315
eppd1033
m06
ee3025
msci231
bb113/bbs1063
fc709
comp3425
comp9417
econ42915
cb9101
math1102e
chme0017
fc307
mkt60104
5522usst
litr1-uc6201.200
ee1102
cosc2803
math39512
omp9727
int2067/int5051
bsb151
mgt253
fc021
babs2202
mis2002s
phya21
18-213
cege0012
mdia1002
math38032
mech5125
07
cisc102
mgx3110
cs240
11175
fin3020s
eco3420
ictten622
comp9727
cpt111
de114102d
mgm320h5s
bafi1019
math21112
efim20036
mn-3503
fins5568
110.807
bcpm000028
info6030
bma0092
bcpm0054
math20212
ce335
cs365
cenv6141
ftec5580
math2010
ec3450
comm1170
ecmt1010
csci-ua.0480-003
econ12-200
ib3960
ectb60h3f
cs247—assignment
tk3163
ics3u
ib3j80
comp20008
comp9334
eppd1063
acct2343
cct109
isys1055/3412
math350-real
math2014
eec180
stat141b
econ2101
msinm014/msing014/msing014b
fit2004
comp643
bu1002
cm2030
联系我们
- QQ: 9951568
© 2021
www.rj363.com
软件定制开发网!