首页
网站开发
桌面应用
管理软件
微信开发
App开发
嵌入式软件
工具软件
数据采集与分析
其他
首页
>
> 详细
data程序讲解、辅导C++程序设计、c/c++编程语言调试 辅导Python程序|讲解留学生Prolog
项目预算:
开发周期:
发布时间:
要求地区:
Computing Machinery I
Assignment 1
8% of your final score
Lead TA
The lead TA for this assignment is Abdullah Sarhan asarhan@ucalgary.ca
Objective
The objective of this assignment is to practice basic C concepts, including 2D arrays, random numbers, and
searching.
Note
It is your responsibility to make sure your code runs on arm.cpsc.ucalgary.ca. Code tested on your
laptop or even linux.ucalgary.ca may not run as desired on arm.cpsc.ucalgary.ca. We will
test your code on the arm servers and we will follow the published marking rubric.
Skills needed for this assignment
• Ability to work with 2D arrays in C
• Ability to use a random number generator
• Ability to employ a searching algorithm
• Ability to use command-line arguments
• Ability to write and read text files in C
• Ability to define functions in C
• Ability to pass parameters by value and by reference
Overview
Your program will implement a simple memory game. The user attempts to match face-down cards. If the
user guesses wrong, the program provides hints.
Details
The game board is a 2D array. The size of which is 2Nx2N where N is a number provided by the user as a
command-line argument. For instance, the program can be started as to initialize a 4x4 grid:
./assign1.o playerName 2
To initialize the values in the board array, follow the steps:
1. Create an array cards of size 2N*N such that card[i] = i.
2. Shuffle the array cards using the following simple algorithm:
for (i = 0; i <2N-2; i++) {
j = random(i,n2*N*N-1); // generate a random number j such that i j n2*N*N-1
swap(cards[i],cards[j]);
}
3. Copy cards to board, one row at a time, starting from row 0.
4. Shuffle cards again
5. Copy cards to the second half board
Once board is initialized print it to the screen:
0 3 7 2
5 6 1 4
3 5 1 2
4 6 0 7
Wait for the user to hit return, then hide your board displaying them face down:
X X X X
X X X X
X X X X
X X X X
You need to clear the screen; you can call Linux clear command from your program as:
system("clear");
The user then selects a card to uncover:
Enter the coordinates of a card: 0 3
The board is re-printed showing card (0,3) uncovered:
X X 7 X
X X X X
X X X X
X X X X
Enter the coordinates of a card: 2 3
X X 7 X
X X X X
X X X 2
X X X X
The user in this example missed to match card 7. So, a hint is provided:
You are 1 card away!
Press any key to continue …
Note that “one card away” means that 7 could be in any of the immediate neighbors of card (2,3). That is,
any of (3,3), (1,3), or (2,2).
When the user continues the game, the mismatched card is flipped back to face down:
X X 7 X
X X X X
X X X X
X X X X
Enter the coordinates of a card: 3 3
This time the user guesses right and the matched cards remain revealed until the end of the game
X X 7 X
X X X X
X X X X
X X X 7
Enter the coordinates of a card:
The user can play the game until all cards are matched, the score becomes 0, or they decide to quit. The
user exists the game by entering q or Q.
The score is calculated as follows. A user starts with a score of 2N. A match adds N points to the score. A
miss subtracts 1 point.
When the user exists or the game ends, the player name and score are recorded in a text file.
Modularity
Your code must be divided into functions as appropriate. At a minimum, you must define the following
functions (we are not showing all necessary arguments, but what is shown must be used as shown):
- initialize(*board)
- shuffle(*cards)
- swap(*cards, i, j)
- randomNum(n,m); n and m are the inclusive lower and upper bounds for the random
number. You can use the C library function rand().
- display(*board)
- findDistance(*board, i1, j1, i2, j2); returns the distance between cards (i1,j1)
and (i2,j2). This distance is 0 if it is a hit; otherwise, the value is used to provide a hint to the user.
- logFile(*playerName, score)
Submission
• Note: The TA may provide further submission instructions
• Name your program assign1.c
• Create a script file and call it assign1.script
• Name your log file assign1.log
• You may submit a README file providing extra instructions or information for your TA
[optional]
• Submit your work to the appropriate dropbox on D2L.
Late Submission Policy
Late submissions will be penalized as follows:
-12.5% is applied for each late day or portion of a day.
Hence, no submissions will be accepted after 8 days (including weekend days) of the announced deadline.
Academic Misconduct
This assignment is to be done by individual students: your final submission must be your own original
work. Teamwork is not allowed. Any similarities between submissions will be further investigated for
academic misconduct. If you discuss the assignment with your colleagues, this must be limited to highlevel
conceptual and design decisions. Code (including pseudo-code) sharing by any means is prohibited,
including but not limited to looking at someone else’s paper or screen, reading code to someone, or reading
pseudo-code. The submission of compiler generated assembly code is absolutely prohibited. Any re-used
code of excess of 5 lines in C and 10 lines in assembly (10 assembly language instructions) must be cited
and have its source acknowledged. Failure to credit the source will also result in a misconduct
investigation.
D2L Marks
Marks posted on D2L are subject to change (up or down).
软件开发、广告设计客服
QQ:99515681
邮箱:99515681@qq.com
工作时间:8:00-23:00
微信:codinghelp
热点项目
更多
urba6006代写、java/c++编程语...
2024-12-26
代做program、代写python编程语...
2024-12-26
代写dts207tc、sql编程语言代做
2024-12-25
cs209a代做、java程序设计代写
2024-12-25
cs305程序代做、代写python程序...
2024-12-25
代写csc1001、代做python设计程...
2024-12-24
代写practice test preparatio...
2024-12-24
代写bre2031 – environmental...
2024-12-24
代写ece5550: applied kalman ...
2024-12-24
代做conmgnt 7049 – measurem...
2024-12-24
代写ece3700j introduction to...
2024-12-24
代做adad9311 designing the e...
2024-12-24
代做comp5618 - applied cyber...
2024-12-24
热点标签
mktg2509
csci 2600
38170
lng302
csse3010
phas3226
77938
arch1162
engn4536/engn6536
acx5903
comp151101
phl245
cse12
comp9312
stat3016/6016
phas0038
comp2140
6qqmb312
xjco3011
rest0005
ematm0051
5qqmn219
lubs5062m
eee8155
cege0100
eap033
artd1109
mat246
etc3430
ecmm462
mis102
inft6800
ddes9903
comp6521
comp9517
comp3331/9331
comp4337
comp6008
comp9414
bu.231.790.81
man00150m
csb352h
math1041
eengm4100
isys1002
08
6057cem
mktg3504
mthm036
mtrx1701
mth3241
eeee3086
cmp-7038b
cmp-7000a
ints4010
econ2151
infs5710
fins5516
fin3309
fins5510
gsoe9340
math2007
math2036
soee5010
mark3088
infs3605
elec9714
comp2271
ma214
comp2211
infs3604
600426
sit254
acct3091
bbt405
msin0116
com107/com113
mark5826
sit120
comp9021
eco2101
eeen40700
cs253
ece3114
ecmm447
chns3000
math377
itd102
comp9444
comp(2041|9044)
econ0060
econ7230
mgt001371
ecs-323
cs6250
mgdi60012
mdia2012
comm221001
comm5000
ma1008
engl642
econ241
com333
math367
mis201
nbs-7041x
meek16104
econ2003
comm1190
mbas902
comp-1027
dpst1091
comp7315
eppd1033
m06
ee3025
msci231
bb113/bbs1063
fc709
comp3425
comp9417
econ42915
cb9101
math1102e
chme0017
fc307
mkt60104
5522usst
litr1-uc6201.200
ee1102
cosc2803
math39512
omp9727
int2067/int5051
bsb151
mgt253
fc021
babs2202
mis2002s
phya21
18-213
cege0012
mdia1002
math38032
mech5125
07
cisc102
mgx3110
cs240
11175
fin3020s
eco3420
ictten622
comp9727
cpt111
de114102d
mgm320h5s
bafi1019
math21112
efim20036
mn-3503
fins5568
110.807
bcpm000028
info6030
bma0092
bcpm0054
math20212
ce335
cs365
cenv6141
ftec5580
math2010
ec3450
comm1170
ecmt1010
csci-ua.0480-003
econ12-200
ib3960
ectb60h3f
cs247—assignment
tk3163
ics3u
ib3j80
comp20008
comp9334
eppd1063
acct2343
cct109
isys1055/3412
math350-real
math2014
eec180
stat141b
econ2101
msinm014/msing014/msing014b
fit2004
comp643
bu1002
cm2030
联系我们
- QQ: 9951568
© 2021
www.rj363.com
软件定制开发网!