首页
网站开发
桌面应用
管理软件
微信开发
App开发
嵌入式软件
工具软件
数据采集与分析
其他
首页
>
> 详细
讲解CS 325编程语言、辅导Python,CS程序、Java编程辅导 调试Matlab程序|辅导留学生 Statistics统计、回归、迭代
项目预算:
开发周期:
发布时间:
要求地区:
Homework 3
Problem 1 (3 points)
Rod Cutting: Show, by means of a counterexample, that the following “greedy” strategy does not
always determine an optimal way to cut rods. Define the density of a rod of length i to be pi / i,
that is, its value per inch. The greedy strategy for a rod of length n cuts off a first piece of length
i, where 1 ≤ i ≤ n, having maximum density. It then continues by applying the greedy strategy to
the remaining piece of length n – i.
Problem 2 (3 points)
Modified Rod Cutting: Consider a modification of the rod-cutting problem in which, in addition
to a price pi for each rod, each cut incurs a fixed cost of c. The revenue associated with a solution
is now the sum of the prices of the pieces minus the costs of making the cuts. Give a dynamicprogramming
algorithm (pseudocode) to solve this modified problem.
Problem 3 (6 points)
Making Change: Given coins of denominations (value) 1 = v1 < v2 < … < vn, we wish to make
change for an amount A using as few coins as possible. Assume that vi’s and A are integers.
Since v1= 1 there will always be a solution. Formally, an algorithm for this problem should take
as input an array V where V[i] is the value of the coin of the ith denomination and a value A
which is the amount of change we are asked to make. The algorithm should return an array C
where C[i] is the number of coins of value V[i] to return as change and m the minimum number
of coins it took. You must return exact change so ∑ V[i] ∙ C[i] = A
𝑛
𝑖=1
The objective is to minimize the number of coins returned or: 𝑚 = 𝑚𝑖𝑛 ∑ C[i]
𝑛
𝑖=1
(a) Describe and give pseudocode for a dynamic programming algorithm to find the minimum
number of coins needed to make change for A.
(b) What is the theoretical running time of your algorithm?
Problem 4 (18 points)
Acme Super Store is having a contest to give away shopping sprees to lucky families. If a family
wins a shopping spree each person in the family can take any items in the store that he or she can
carry out, however each person can only take one of each type of item. For example, one family
member can take one television, one watch and one toaster, while another family member can
take one television, one camera and one pair of shoes. Each item has a price (in dollars) and a
weight (in pounds) and each person in the family has a limit in the total weight they can carry.
Two people cannot work together to carry an item. Your job is to help the families select items
for each person to carry to maximize the total price of all items the family takes.
(a) Write an efficient algorithm (verbal description and pseudo-code) to determine the maximum
total price of items for each family and the items that each family member should select.
(b) What is the theoretical running time of your algorithm for one test case given N items, a
family of size F, and family members who can carry at most Mi pounds for 1 ≤ i ≤ F.
(c) Implement your algorithm by writing a program named “shopping”. The program should
satisfy the specifications below.
Input: The input file named “shopping.txt” consists of T test cases
T (1 ≤ T ≤ 100) is given on the first line of the input file.
Each test case begins with a line containing a single integer number N that indicates the
number of items (1 ≤ N ≤ 100) in that test case
Followed by N lines, each containing two integers: P and W. The first integer (1 ≤ P ≤
5000) corresponds to the price of object and the second integer (1 ≤ W ≤ 100) corresponds
to the weight of object.
The next line contains one integer (1 ≤ F ≤ 30) which is the number of people in that
family.
The next F lines contains the maximum weight (1 ≤ M ≤ 200) that can be carried by the ith
person in the family (1 ≤ i ≤ F).
Output: Written to a file named “results.txt”. For each test case your program should output the
maximum total price of all goods that the family can carry out during their shopping spree and
for each the family member, numbered 1 ≤ i ≤ F, list the item numbers 1 ≤ N ≤ 100 that they
should select. List both family members and the corresponding items in order.
Sample Input (comments are not part of the file, they are added for clarification)
2 // 2 test cases
3 // 3 items for test case 1
72 17 // P and W of item 1 (case 1)
44 23 // P and W of item 2 (case 1)
31 24 // P and W of item 3 (case 1)
1 // 1 family member (case 1)
26 // max weight for family member 1 (case 1)
6 // 6 items for test case 2
64 26 // P and W of item 1 (case 2)
Sample Output (in some cases, there are multiple solutions, providing only one of these
solutions is enough)
软件开发、广告设计客服
QQ:99515681
邮箱:99515681@qq.com
工作时间:8:00-23:00
微信:codinghelp
热点项目
更多
代做ceng0013 design of a pro...
2024-11-13
代做mech4880 refrigeration a...
2024-11-13
代做mcd1350: media studies a...
2024-11-13
代写fint b338f (autumn 2024)...
2024-11-13
代做engd3000 design of tunab...
2024-11-13
代做n1611 financial economet...
2024-11-13
代做econ 2331: economic and ...
2024-11-13
代做cs770/870 assignment 8代...
2024-11-13
代写amath 481/581 autumn qua...
2024-11-13
代做ccc8013 the process of s...
2024-11-13
代写csit040 – modern comput...
2024-11-13
代写econ 2070: introduc2on t...
2024-11-13
代写cct260, project 2 person...
2024-11-13
热点标签
mktg2509
csci 2600
38170
lng302
csse3010
phas3226
77938
arch1162
engn4536/engn6536
acx5903
comp151101
phl245
cse12
comp9312
stat3016/6016
phas0038
comp2140
6qqmb312
xjco3011
rest0005
ematm0051
5qqmn219
lubs5062m
eee8155
cege0100
eap033
artd1109
mat246
etc3430
ecmm462
mis102
inft6800
ddes9903
comp6521
comp9517
comp3331/9331
comp4337
comp6008
comp9414
bu.231.790.81
man00150m
csb352h
math1041
eengm4100
isys1002
08
6057cem
mktg3504
mthm036
mtrx1701
mth3241
eeee3086
cmp-7038b
cmp-7000a
ints4010
econ2151
infs5710
fins5516
fin3309
fins5510
gsoe9340
math2007
math2036
soee5010
mark3088
infs3605
elec9714
comp2271
ma214
comp2211
infs3604
600426
sit254
acct3091
bbt405
msin0116
com107/com113
mark5826
sit120
comp9021
eco2101
eeen40700
cs253
ece3114
ecmm447
chns3000
math377
itd102
comp9444
comp(2041|9044)
econ0060
econ7230
mgt001371
ecs-323
cs6250
mgdi60012
mdia2012
comm221001
comm5000
ma1008
engl642
econ241
com333
math367
mis201
nbs-7041x
meek16104
econ2003
comm1190
mbas902
comp-1027
dpst1091
comp7315
eppd1033
m06
ee3025
msci231
bb113/bbs1063
fc709
comp3425
comp9417
econ42915
cb9101
math1102e
chme0017
fc307
mkt60104
5522usst
litr1-uc6201.200
ee1102
cosc2803
math39512
omp9727
int2067/int5051
bsb151
mgt253
fc021
babs2202
mis2002s
phya21
18-213
cege0012
mdia1002
math38032
mech5125
07
cisc102
mgx3110
cs240
11175
fin3020s
eco3420
ictten622
comp9727
cpt111
de114102d
mgm320h5s
bafi1019
math21112
efim20036
mn-3503
fins5568
110.807
bcpm000028
info6030
bma0092
bcpm0054
math20212
ce335
cs365
cenv6141
ftec5580
math2010
ec3450
comm1170
ecmt1010
csci-ua.0480-003
econ12-200
ib3960
ectb60h3f
cs247—assignment
tk3163
ics3u
ib3j80
comp20008
comp9334
eppd1063
acct2343
cct109
isys1055/3412
math350-real
math2014
eec180
stat141b
econ2101
msinm014/msing014/msing014b
fit2004
comp643
bu1002
cm2030
联系我们
- QQ: 9951568
© 2021
www.rj363.com
软件定制开发网!